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mysql 时间间隔查询

select count(*) from sometable where datetimecolumn>=UNIX_TIMESTAMP('2010-03-01 00:00:00') and datetimecolumn

datediff DATEDIFF(expr,expr2) DATEDIFF() 返回起始时间 expr和结束时间expr2之间的天数。Expr和expr2 为日期或 date-and-time 表达式。计算中只用到这些值的日期部分。 mysql> SELECT DATEDIFF('1997-12-31 23:59:59','1997-12-30'); -> 1 mys...

select * from table where 时间字段 between '2010-7-12 11:18:54' and '2010-7-12 11:22:20'

你表中的数据,根据你的题目,应该是全部显示才对。是小于5秒还是5分钟? 下面这个是 两条数据间小于5秒的记录的查询语句 select *,timestampdiff(second,t1.time,(select time from table3 where t1.idid order by id desc limit 1),t1.time ) ...

select dtime,name from(select name,dtime,rank,ptime,ptime2 from(select cg_tmp.*, @rownum :=@rownum + 1,if(TIMESTAMPDIFF(MINUTE, @ptime,cg_tmp.dtime)

1. sql 中字段不要加‘ ’ =>select *, caozuo as caozuo from mj_searched (多此一举吗? 有*了 还艺单独查caozuo) 2. select *, caozuo as caozuo from mj_searched where publishedtime >= '2013-02-12' AND publishedtime

一楼的写错,二楼的乱写, 假设存在一主键列id select * from 表 where id in(select id from 表 group by id haing count(数据列)=3) 这句就行了~

mysql常用的日期加减函数与实例教程 MySQL 日期类型 MySQL 日期类型:日期格式、所占存储空间、日期范围 比较。 日期类型 存储空间 日期格式 日期范围 ------------ --------- --------------------- -----------------------------------------...

时间段统计,可以采用 hour(subscribe_time) 取出小时然后分层。思路: select uid ,CASE WHEN HOUR(subscribe_time) BETWEEN 0 AND 1 THEN '00:00:00' WHEN HOUR(subscribe_time) BETWEEN 2 AND 3 THEN '02:00:00' ... ELSE '23:00:00' END -- ...

SELECT DATE_FORMAT(time,'%Y-%m-%d') as day, sum(case when amount>0 then amount when amount=0 then 0 end) as amount1 from table where time>='2014-11-01' group by day; 我没有测试。time表示日期,amount表示数量。查询11月后每天成交数量

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